Solutions to Math 1411- Test 1
1. Estimate the limit by substituting smaller and smaller values of h. If the values start to cluster about a certain number, that number is the limit. Give answer to three decimal places.
            
a.         
Answer: 1.099
Solution:
| 
 | 
 | 
| 0.1 | 1.16123 | 
| 0.001 | 1.09921 | 
| 0.00001 | 1.09862 | 
| 0.0000001 | 1.09861 | 
| 0.000000001 | 1.0986 | 
Since the 
instructions were to round to three decimals, then   .
.
b.         

Answer: 1.359
Solution:
| 
 | 
 | 
| 0.1 | 1.42942 | 
| 0.001 | 1.35982 | 
| 0.00001 | 1.359148 | 
| 0.0000001 | 1.359141 | 
| 0.000000001 | 1.35915 | 
Since the instructions were to round 
to three decimals, them  
2. Use the following figure to give approximate values for the following limits (if they exist).
            
a.          
        
Answer: 3
Solution: As you evaluate the function visually from the graph, the function values get closer and closer to 3 as x approaches – 4 from the left and as x approaches – 4 from the right.
b.         

Answer: The Limit Does Not Exist.
Solution:         
As you approach – 1 from the left, the function values approach 
2.  As you approach – 1 from the right, the function values approach 
5.   Therefore, there is no limit at 
c.         

Answer: The Limit Does Not Exist
Solution:         
As you approach 2 from the left, the function values approach 3.  As you 
approach 2 from the right, the function values approach 2.   
Therefore, there is no limit at 
d.         

Answer: 0.5
Solution: As you evaluate the function visually from the graph, the function values get closer and closer to 0.5 as x approaches 6 from the left and as x approaches 6 from the right.

3.         
If  and
 and 
 , evaluate the 
following limits if they exit.  If they do not exist, explain why.
, evaluate the 
following limits if they exit.  If they do not exist, explain why.
            
a.         
Answer: -9
Solution:         

Remember that polynomials are continuous everywhere.
b.         

Answer: 0
Solution:         
 The function
   
The function   is only undefined at
 is only undefined at 
                        
Therefore   .
.
            
c.         
Answer: The Limit Does Not Exist
Solution:         
 The function
   
The function  is undefined at
 is undefined at  .  Therefore, the limit does 
not exist at
.  Therefore, the limit does 
not exist at  .
.
            
d.         
Answer: 13
Solution:         
Both of the functions are polynomials and  is a polynomial.  
Polynomials are continuous everywhere; therefore,
 is a polynomial.  
Polynomials are continuous everywhere; therefore,

4. You have $500 invested in a bank account earning 8.2% compounded annually.
a. Write an equation for the money M in your account after t years.
Answer:          

Solution: Since the money is increasing at an annual rate of 8.2%, the base is 1.082.
b. How long will it take to triple your money?
Answer: 13.94 Years
Solution:         


c. Suppose the interest were compounded monthly instead, that is you earned interest each month. What interest would you then earn for 1 year?
Answer: 8.52%
Solution:         
At the end of one year, one dollar grows to  .  So the annualized rate is 
8.52%.
.  So the annualized rate is 
8.52%.
5. Find a possible formula for each of the following functions. Check that your formula fits the data points.

(a) 
Answer:     
Solution:         
This can either be represented by a sine function or a cosine function.  
Since the highest point is on the y-axis, let’s use the cosine function. The 
typical model for the cosine function is  .
.
                        
Since the highest point of the graph is on the y-axis, there is no 
horizontal shift and thus  .
.  
Two full cycles occur in 8 
units; therefore, the period is 4 units.  Since  , then
, then  .
.  
A represents the amplitude which is half the distance between the highest point and the lower point or 2.5.
D represents the midpoint which is 5.
 is the correct model.  
Let’s check it with the point
 is the correct model.  
Let’s check it with the point  .
.   
           
(b) 
Answer:     
Solution:         
This is an exponential function of the form  .  Using the point
.  Using the point  yields
 yields  .  Using the other 
two points, we get
.  Using the other 
two points, we get

Let’s check it with the 
point  .
.  

(c) 
Answer:     
Solution:         
This is a polynomial of degree 3 with a zero at  and a double zero at
 and a double zero at 
 .  We can 
write it as
.  We can 
write it as  . 
 Use the point
. 
 Use the point  to find the value of a.
 to find the value of a.   and
 and  .
.
                        
 can be 
written as
 can be 
written as 
Let’s check it with the 
point  .
.  
