Solutions to Math 1411- Test 1

 

 

1.         Estimate the limit by substituting smaller and smaller values of h.  If the values start to cluster about a certain number, that number is the limit.  Give answer to three decimal places.

            a.        

Answer:          1.099

Solution:        

0.1

1.16123

0.001

1.09921

0.00001

1.09862

0.0000001

1.09861

0.000000001

1.0986

Since the instructions were to round to three decimals, then  .

b.        

Answer:          1.359

Solution:        

0.1

1.42942

0.001

1.35982

0.00001

1.359148

0.0000001

1.359141

0.000000001

1.35915

Since the instructions were to round to three decimals, them 

 

 

 

 

 

 

 

2.         Use the following figure to give approximate values for the following limits (if they exist).

            a.                

Answer:          3

Solution:         As you evaluate the function visually from the graph, the function values get closer and closer to 3 as x approaches – 4 from the left and as x approaches – 4 from the right.

b.        

Answer:          The Limit Does Not Exist.

Solution:         As you approach – 1 from the left, the function values approach 2.  As you approach – 1 from the right, the function values approach 5.   Therefore, there is no limit at

c.        

Answer:          The Limit Does Not Exist

Solution:         As you approach 2 from the left, the function values approach 3.  As you approach 2 from the right, the function values approach 2.   Therefore, there is no limit at

d.        

Answer:          0.5

Solution:         As you evaluate the function visually from the graph, the function values get closer and closer to 0.5 as x approaches 6 from the left and as x approaches 6 from the right.

 

 

 

 

 

 

 

 

 

3.         If  and , evaluate the following limits if they exit.  If they do not exist, explain why.

            a.        

Answer:          -9

Solution:        

                        Remember that polynomials are continuous everywhere.

b.        

Answer:          0

Solution:            The function   is only undefined at

                        Therefore  .

            c.        

Answer:          The Limit Does Not Exist

Solution:            The function  is undefined at .  Therefore, the limit does not exist at .

            d.        

Answer:          13

Solution:         Both of the functions are polynomials and  is a polynomial.  Polynomials are continuous everywhere; therefore,

 

 

 

 

 

 

 

 

 

4.         You have $500 invested in a bank account earning 8.2% compounded annually.

            a.         Write an equation for the money M in your account after t years.

Answer:         

Solution:         Since the money is increasing at an annual rate of 8.2%, the base is 1.082.

            b.         How long will it take to triple your money?       

Answer:          13.94 Years

Solution:        

 

c.         Suppose the interest were compounded monthly instead, that is you earned  interest each month.  What interest would you then earn for 1 year?

Answer:          8.52%

Solution:         At the end of one year, one dollar grows to .  So the annualized rate is 8.52%.

 

 

 

 

 

5.         Find a possible formula for each of the following functions.  Check that your formula fits the data points.

 

 

(a) Answer:    

Solution:         This can either be represented by a sine function or a cosine function.  Since the highest point is on the y-axis, let’s use the cosine function. The typical model for the cosine function is .

                        Since the highest point of the graph is on the y-axis, there is no horizontal shift and thus

Two full cycles occur in 8 units; therefore, the period is 4 units.  Since , then

A represents the amplitude which is half the distance between the highest point and the lower point or 2.5.

D represents the midpoint which is 5.

 is the correct model.  Let’s check it with the point           

 

(b) Answer:    

Solution:         This is an exponential function of the form .  Using the point  yields .  Using the other two points, we get

Let’s check it with the point

 

 

(c) Answer:    

Solution:         This is a polynomial of degree 3 with a zero at  and a double zero at .  We can write it as .  Use the point  to find the value of a.   and .

                         can be written as

 

Let’s check it with the point

 


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Author: Dr. Nancy Marcus